PHP single column value :
$post_like_id=mysql_query("SELECT * FROM `post_answer` WHERE `postid` = '$questionID'");
$post_answer = mysql_fetch_array($post_like_id);
$like=$post_answer['p_id'];
1 — KISS (Keep It Simple, Stupid) Simplicity triumphs over complexity. Direct and clear codes are better for developing, maintaining, and s...
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